x^2+1,5x-1.44=0

Solution for x^2+1,5x-1.44=0 equation:

x^2+1.5x-1.44=0

a = 1; b = 1.5; c = -1.44;
Δ = b2-4ac
Δ = 1.52-4·1·(-1.44)
Δ = 8.01
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.5)-\sqrt{8.01}}{2*1}=\frac{-1.5-\sqrt{8.01}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.5)+\sqrt{8.01}}{2*1}=\frac{-1.5+\sqrt{8.01}}{2}
$